25p^2-30p-13=-6

Solution for 25p^2-30p-13=-6 equation:

25p^2-30p-13=-6

We move all terms to the left:

25p^2-30p-13-(-6)=0

We add all the numbers together, and all the variables

25p^2-30p-7=0

a = 25; b = -30; c = -7;
Δ = b2-4ac
Δ = -302-4·25·(-7)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-40}{2*25}=\frac{-10}{50}
=-1/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+40}{2*25}=\frac{70}{50}
=1+2/5
$